Energy equals power times time. Power is the work input. For a lighting system, the power is the wattage of the system. A 60 watt incandescent lamp uses 60 watts of power to operate. Since utilities measure usage for an entire building, they use kilowatts or thousands of watts. So a utility would measure the 60 watt lamp as .06 kW. Utilities refer to the monthly kW reading as demand.
Utilities factor in the amount of time power is used, typically in hours. So, energy is the measure of power used, measured in kilowatts per hour, or kWh. For example, if the 60-watt lamp operates for ten hours a day, then it will use 60 watts times ten hours divided by 1000 watts/kW or 0.6 kWh per day. Most utilities charge residential and small commercial customers only for the energy, or kWh, they use in a month. However, for larger commercial and industrial customers, most utilities will base the charges on both the energy and the monthly demand reading.
It pays to be familiar with the specific rate schedules in order to understand energy billing. Utilities base the demand charge on the highest fifteen or thirty minute average demand that occurs during a month. Sometimes a rate schedule is set up to include a " billing demand". The billing demand is the highest of either the current month's demand or a percentage of the highest demand from the previous eleven months. Demand is a very real component of a utility bill and will impact the costs and savings of lighting projects.
Here are a few examples of how to calculate energy and cost savings on electric bills from the installation of energy efficient lighting.
To calculate the energy savings, just figure the difference between the existing energy usage and the proposed energy usage.
The Energy Savings would equal the existing energy usage 12,480 kWh/year minus the proposed energy usage 3,120 kWh/year or 9,360 kWh/year. To calculate the cost savings, just multiply the annual energy savings times the charge per kWh for electricity (eight cents in this case).
The existing demand equals the power 6 kW, or 100 lamps times 60-watts per
lamp divided by 1000 watts per kilowatt.
The proposed demand equals 100 lamps times 15-watts per lamp divided by 1000
watts per kilowatt, or 1.5 kW.
The demand savings equals 6 kW minus 1.5 kW, or 4.5 kW. Since the utility
measures demand each month, the demand savings is 4.5 kW per month. The energy cost savings are the same as before, 9,360 kWh per year times $0.04
per kWh equals $374.40 per year. The demand cost savings is the demand saved per month times 12 months per year
times the cost per kW demand. So, 4.5 kW per month times 12 months per year
times $9.75 per kW equals $526.50 per year.